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		<h1>Đề thi học sinh giỏi huyện môn hóa 9 năm học 2008-2009</h1>
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			Đề thi học sinh giỏi huyện môn hóa 9 năm học 2008-2009
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			Đề thi học sinh giỏi huyện môn hóa 9 năm học 2008-2009
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			<td style="width:264px; padding:0cm 7px 0cm 7px" valign="top"><span style="font-size:12pt"><span style="font-family:&#039;Times New Roman&#039;">PH<u>ÒNG GD-ĐT THẠCH</u> HÀ</span></span><br />
			<span style="font-size:12pt"><span style="font-family:&#039;Times New Roman&#039;">&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</span></span></td>
			<td style="width:487px; padding:0cm 7px 0cm 7px" valign="top"><span style="font-size:12pt"><span style="font-family:&#039;Times New Roman&#039;"><b><span lang="EN-US" style="font-size:14.0pt">KÌ THI HỌC SINH GIỎI HUYỆN LỚP 9</span></b></span></span><br />
			<span style="font-size:12pt"><span style="font-family:&#039;Times New Roman&#039;"><b><span lang="EN-US" style="font-size:14.0pt">Năm học:2008-2009</span></b></span></span><br />
			<span style="font-size:12pt"><span style="font-family:&#039;Times New Roman&#039;"><b><span lang="EN-US" style="font-size:14.0pt">&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; Môn thi:Hoá học&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; Thời gian: 150 phút</span></b></span></span><br />
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<span style="font-size:12pt"><span style="line-height:150%"><span style="font-family:&#039;Times New Roman&#039;">&nbsp;</span></span></span><br />
<span style="font-size:12pt"><span style="font-family:&#039;Times New Roman&#039;"><b><i><u><span lang="EN-US" style="font-size:14.0pt">Câu1</span></u></i></b><span lang="EN-US" style="font-size:14.0pt">. Hoàn thành chuỗi phản ứng hoá học sau:</span></span></span><br />
<br />
<span style="font-size:12pt"><span style="font-family:&#039;Times New Roman&#039;"><span style="position:absolute; margin-left:91px; margin-top:8px; width:29px"><span style="z-index:4"><span style="height:18px"><img alt="" src="https://thcsphanhuychu.edu.vn/file:///C:\Users\vx\AppData\Local\Temp\msohtml1\01\clip_image001.gif" style="width:29px; height:18px" /></span></span></span> <span style="position:absolute; margin-left:138px; margin-top:14px; width:12px"><span style="z-index:9"><span style="height:27px"><img alt="" src="https://thcsphanhuychu.edu.vn/file:///C:\Users\vx\AppData\Local\Temp\msohtml1\01\clip_image002.gif" style="width:12px; height:27px" /></span></span></span> <span style="position:absolute; margin-left:287px; margin-top:7px; width:27px"><span style="z-index:8"><span style="height:12px"><img alt="" src="https://thcsphanhuychu.edu.vn/file:///C:\Users\vx\AppData\Local\Temp\msohtml1\01\clip_image003.gif" style="width:27px; height:12px" /></span></span></span> <span style="position:absolute; margin-left:234px; margin-top:17px; width:12px"><span style="z-index:5"><span style="height:27px"><img alt="" src="https://thcsphanhuychu.edu.vn/file:///C:\Users\vx\AppData\Local\Temp\msohtml1\01\clip_image002.gif" style="width:12px; height:27px" /></span></span></span> <span style="position:absolute; margin-left:167px; margin-top:5px; width:27px"><span style="z-index:1"><span style="height:12px"><img alt="" src="https://thcsphanhuychu.edu.vn/file:///C:\Users\vx\AppData\Local\Temp\msohtml1\01\clip_image004.gif" style="width:27px; height:12px" /></span></span></span><span lang="PT-BR" style="font-size:14.0pt">&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; <sup>1</sup>&nbsp;&nbsp;&nbsp; FeCl<sub>2</sub>&nbsp;&nbsp; <sup>2</sup>&nbsp;&nbsp;&nbsp; Fe(NO<sub>3</sub>)<sub>2</sub>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; <sup>3</sup>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; Fe(OH)<sub>2</sub></span></span></span><br />
<span style="font-size:12pt"><span style="font-family:&#039;Times New Roman&#039;"><span style="position:absolute; margin-left:407px; margin-top:8px; width:29px"><span style="z-index:10"><span style="height:19px"><img alt="" src="https://thcsphanhuychu.edu.vn/file:///C:\Users\vx\AppData\Local\Temp\msohtml1\01\clip_image005.gif" style="width:29px; height:19px" /></span></span></span> <span style="position:absolute; margin-left:342px; margin-top:3px; width:12px"><span style="z-index:7"><span style="height:27px"><img alt="" src="https://thcsphanhuychu.edu.vn/file:///C:\Users\vx\AppData\Local\Temp\msohtml1\01\clip_image006.gif" style="width:12px; height:27px" /></span></span></span> <span style="position:absolute; margin-left:90px; margin-top:10px; width:30px"><span style="z-index:3"><span style="height:30px"><img alt="" src="https://thcsphanhuychu.edu.vn/file:///C:\Users\vx\AppData\Local\Temp\msohtml1\01\clip_image007.gif" style="width:30px; height:30px" /></span></span></span><span lang="PT-BR" style="font-size:14.0pt">&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; Fe&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; <sup>5</sup>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; </span><span lang="PT-BR" style="font-size:10.0pt">7 </span>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;<span lang="PT-BR" style="font-size:10.0pt">9 </span><span lang="PT-BR" style="font-size:14.0pt">&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;Fe<sub>2</sub>O<sub>3</sub></span></span></span><br />
<span style="font-size:12pt"><span style="font-family:&#039;Times New Roman&#039;"><span style="position:absolute; margin-left:287px; margin-top:8px; width:27px"><span style="z-index:6"><span style="height:12px"><img alt="" src="https://thcsphanhuychu.edu.vn/file:///C:\Users\vx\AppData\Local\Temp\msohtml1\01\clip_image008.gif" style="width:27px; height:12px" /></span></span></span> <span style="position:absolute; margin-left:179px; margin-top:7px; width:27px"><span style="z-index:2"><span style="height:12px"><img alt="" src="https://thcsphanhuychu.edu.vn/file:///C:\Users\vx\AppData\Local\Temp\msohtml1\01\clip_image009.gif" style="width:27px; height:12px" /></span></span></span>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; <sup><span lang="ES-VE" style="font-size:14.0pt">4</span></sup><span lang="ES-VE" style="font-size:14.0pt">&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; FeCl<sub>3 </sub>&nbsp;&nbsp;&nbsp;&nbsp;<sup>6</sup>&nbsp; Fe(NO<sub>3</sub>)<sub>3 </sub>&nbsp;&nbsp;&nbsp;&nbsp;<sup>8</sup>&nbsp;&nbsp;&nbsp; Fe(OH)<sub>3</sub>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; <sup>10</sup></span></span></span><br />
<span style="font-size:12pt"><span style="line-height:150%"><span style="font-family:&#039;Times New Roman&#039;"><b><i><u><span lang="ES-VE" style="font-size:14.0pt"><span style="line-height:150%">Câu2</span></span></u></i></b><span lang="ES-VE" style="font-size:14.0pt"><span style="line-height:150%">. Bằng phương pháp hoá học,không dùng thêm hoá chất nào khác nêu cách nhận biết 4 dung dịch sau:NaCl ; Ba(OH)<sub>2</sub> ; H<sub>2</sub>SO<sub>4</sub> ; NaHCO<sub>3</sub>.Viết các phương trình phản ứng. </span></span></span></span></span><br />
<span style="font-size:12pt"><span style="line-height:150%"><span style="font-family:&#039;Times New Roman&#039;"><b><i><u><span lang="ES-VE" style="font-size:14.0pt"><span style="line-height:150%">Câu3</span></span></u></i></b><span lang="ES-VE" style="font-size:14.0pt"><span style="line-height:150%">. Cần thêm bao nhiêu gam SO<sub>3</sub> vào dung dịch H<sub>2</sub>SO<sub>4 </sub>9,8% để được 500 gam dung dịch H<sub>2</sub>SO<sub>4</sub> 54,88%.</span></span></span></span></span><br />
<span style="font-size:12pt"><span style="line-height:150%"><span style="font-family:&#039;Times New Roman&#039;"><b><i><u><span lang="ES-VE" style="font-size:14.0pt"><span style="line-height:150%">Câu4</span></span></u></i></b><span lang="ES-VE" style="font-size:14.0pt"><span style="line-height:150%">. Hấp thụ hoàn toàn V lít SO<sub>2</sub> (đktc) vào 975 gam dung dịch KOH 11,2% sau khi phản ứng kết thúc làm bay hơi nước cẩn thận thu được 172,5 gam muối khan.Tính V.</span></span></span></span></span><br />
<span style="font-size:12pt"><span style="line-height:150%"><span style="font-family:&#039;Times New Roman&#039;"><b><i><u><span lang="ES-VE" style="font-size:14.0pt"><span style="line-height:150%">Câu5</span></span></u></i></b><span lang="ES-VE" style="font-size:14.0pt"><span style="line-height:150%">. Cho một oxit kim loại hoá trị II tác dụng vừa đủ với dung dịch H<sub>2</sub>SO<sub>4 </sub>20% sau phản ứng kết thúc thu được dung dịch muối sunfat có nồng độ 22,64%.Tìm oxit kim loại trên.</span></span></span></span></span><br />
<span style="font-size:12pt"><span style="line-height:150%"><span style="font-family:&#039;Times New Roman&#039;"><b><i><u><span lang="ES-VE" style="font-size:14.0pt"><span style="line-height:150%">Câu6</span></span></u></i></b><span lang="ES-VE" style="font-size:14.0pt"><span style="line-height:150%">. Cho dung dịch H<sub>2</sub>SO<sub>4 </sub>loãng dư tác dụng với hợp kim Mg và Fe sau phản ứng kết thúc thu được 2,016 lít khí H<sub>2</sub> (đktc).Nếu cũng lượng hợp kim này tác dụng với dung dịch FeSO<sub>4</sub> dư sau phản ứng kết thúc khối lượng kim loại tăng thêm 1,68 gam.Tính khối lượng mỗi kim loại trong hợp kim.</span></span></span></span></span><br />
<span style="font-size:12pt"><span style="line-height:150%"><span style="font-family:&#039;Times New Roman&#039;"><b><i><u><span lang="ES-VE" style="font-size:14.0pt"><span style="line-height:150%">Câu7</span></span></u></i></b><span lang="ES-VE" style="font-size:14.0pt"><span style="line-height:150%">.Khử hoàn toàn 142 gam hỗn hợp A gồm Fe<sub>2</sub>O<sub>3 </sub>; Fe<sub>3</sub>O<sub>4</sub> và FeO thì cần 53,76 lít khí CO (đktc).Mặt khác để hoà tan 142 gam hổn hợp A trong dung dịch H<sub>2</sub>SO<sub>4 </sub>đặc nóng dư thì thu được V lít khí SO<sub>2</sub>(đktc).Tính V.</span></span></span></span></span><br />
<span style="font-size:12pt"><span style="line-height:150%"><span style="font-family:&#039;Times New Roman&#039;"><b><i><u><span lang="ES-VE" style="font-size:14.0pt"><span style="line-height:150%">Câu8</span></span></u></i></b><span lang="ES-VE" style="font-size:14.0pt"><span style="line-height:150%">. Đốt cháy hoàn toàn 18 gam A bằng một lượng ôxi vừa đủ sau phản ứng kết thúc thu được 35,2 gam CO<sub>2</sub> ; 25,2 gam H<sub>2</sub>O và 4,48 lít N<sub>2</sub>(đktc).Tìm công thức phân tử của A.Biết rằng 0,15 mol A có khối lượng 6,75 gam.</span></span></span></span></span><br />
<br />
<span style="font-size:12pt"><span style="line-height:150%"><span style="font-family:&#039;Times New Roman&#039;"><span lang="ES-VE" style="font-size:14.0pt"><span style="line-height:150%">&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;-------Hết---------</span></span></span></span></span><br />
<span style="font-size:12pt"><span style="line-height:150%"><span style="font-family:&#039;Times New Roman&#039;"><span lang="ES-VE" style="font-size:14.0pt"><span style="line-height:150%">&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; Ghi chú: Thí sinh được sử dụng bảng hệ thống tuần hoàn các nguyên tố hoá học.</span></span></span></span></span><br />
<br />
&nbsp;
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				<strong>Tác giả bài viết:</strong>
				Nguyễn Công Hải
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